LeetCode 278.
Tags: LeetCode
Intuition
Binary Seaching to find the answer
Approach
Binary Seaching
Complexity
-
Time complexity: O(logn)
-
Space complexity: O(1)
Code
class Solution {
public int firstBadVersion(int n) {
int left = 1, right = n, mid = left + (right - left) / 2;
while (left <= right) {
if (left == right) return left;
mid = left + (right - left) / 2;
if (isBadVersion(mid)) {
right = mid;
}else{
left = mid + 1;
}
}
return mid;
}
}
Check out the description of this problem at LC 278.